Wednesday, April 11, 2012

IITs lift curtain, reveal JEE cut-off marks

The Indian Institutes of Technology (IITs) have finally emerged from their veil of secrecy, revealing the cut-off marks for gaining admission through the just-concluded Joint Entrance Examination (IIT-JEE). For the first time in IIT-JEE’s five-decade history, the chain of institutes has revealed the minimum qualifying marks in each subject, and in aggregate form for various categories of students.

While a general category student will have to get 10% in each subject, the minimum qualifying marks would be 9% for other backward class (OBC) students, and 5% for scheduled caste (SC), scheduled tribe (ST) as well as physically disabled (PD) students. In addition to this, the student would have to clear the aggregate cut to be eligible for being a part of the all-india ranking. While the aggregate cut-off for the general category is 35%, it is 31.5% for OBCS and 17.5% for SC, ST and PD.

This means that if a general category student scores 14 marks out of 136 in all the three subjects — physics, chemistry and mathematics — and has an overall aggregate cut-off of 143 out of 408 marks, he or she will be eligible for the rank. According to IIT professors, providing the qualifying marks will help students evaluate their performance as soon as they leave the IIT-JEE examination centre, and reduce stress on students. It will also help them prepare for the examination, they added.

Welcoming the move, a parent of an aspiring IIT student suggested that the institutes upload the answer keys of the question papers after the examination. “It will further help students evaluate their performance and reduce their dependence on coaching centres,” he said. The decision is an outcome of the Supreme Court’s observations in a case filed by IIT-Kharagpur professor Rajiv Kumar, who was hailed as an unsung hero for bringing transparency into the IIT-JEE examination system.

Source: Hindustan Times, April 11, 2012

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